Puzzle No. 512: Kurotto

Since I’ve just been back here recently, I should note that sometimes, I won’t be posting “fresh” puzzles. Mostly this is because I also want to use the blog to organize some of these puzzles better.

I have been participating in “speedsetting” contests lately over on the CTC discord server. I’ve seen that this may seem unappealing to some more experienced puzzlemakers, but honestly, its a lot of fun. Also, mostly it allows me to put together something without overthinking about “where will it get published” and “what are the requirements”, while being in a limited time setting that makes me “feel” like I am doing something different.

What about the quality of the puzzle then? I’ll let you be the judge, with today’s puzzle, which is from a speedsetting event that took place just 6 or 7 hours ago. The constraints given were to construct a Kurotto with the only clues being in sets of 3 orthogonally connected cells, of the same shape (allowing for rotations and reflections). Basically, either a puzzle with only L trimino sets of clues or a puzzle with only I trimino sets of clues. The time given was 40 minutes but I forgot about it and joined late. Fortunately, its Kurotto, probably as comfortable for me as Tapa, so I could whip this up in 5-6 minutes. It won 2nd place!

I have more puzzles from earlier speedsetting contests that I’ll be posting in the future, but for now, here is the Kurotto!

Rules: Shade some cells so that each circled number represents the total count of shaded cells in connected groups sharing an edge with that number. Cells with circles cannot be shaded.

Link to solve on Penpa: https://git.io/JRqze

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One comment on “Puzzle No. 512: Kurotto

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